WebKOH solution added. Round your answer to 2 decimal places. pH = 0 X 00. 18 Ar. An analytical chemist is titrating 198.9 mL of a 1.100M solution of hydrazoic acid (HN3) with a 0.3900M solution of KOH. The pK of hydrazoic acid is 4.72. Calculate the pH of the acid solution after the chemist has added 653.4 mL of the KOH solution to it. WebThe pH of a 0.25 M aqueous solution of an acid, HA, at 25. 0 ∘ C is 2.03 . What is the value of K a for HA? 6.0 × 1 0 − 5 3.5 × 1 0 − 4 none of the above 2.0 × 1 0 − 9 1.1 × 1 0 − 9
SOLVED: Determine the pH of each 1.) 0.25 M KCHO2 …
WebMar 1, 2012 · 2 answers You looked up Kb which is right. You want Ka for CH3NH3^+ and they don't make tables for those. You ALWAYS know that KaKb=Kw; therefore, if you have Kb and want Ka it's Ka = Kw/Kb. If you have Ka and want Kb it's Kb = Kw/Ka. answered by DrBob222 March 1, 2012 Try equaling it (The Ka to the equation you found) to find the … WebAnd we get 3.73 times 10 to the -6 Ph will then be the negative blog of the hydro knee um concentration and the hydro knee um concentration. If the hydroxide concentration divided into KW After we get the hydro knee um concentration will take the negative log and get a ph of 857 for the next one we have an acid We have an acid a conjugate acid ... floating shelves invisible brackets
Determine the ph of the following solutions...? - AnswerData
WebAug 30, 2015 · Since Ka is small compared with the initial concentration of the acid, you can approximate (0.20− x) with 0.20. This will give you Ka = x2 0.2 ⇒ x = √0.2 ⋅ 1.78 ⋅ 10−4 = 5.97 ⋅ 10−3 The concentration of the hydronium ions will thus be x = [H3O+] = 5.97 ⋅ 10−3M This means that the solution's pH will be pH sol = − log([H3O+]) WebNov 19, 2024 · Determine the pH of each of the following solutions. Part A: 0.24 M KCHO2 Express your answer to two decimal places. Part B: 0.25 M CH3NH3I Express your answer to two decimal places. Part C: 0.17 M KI Express your answer to two decimal places. Answer + 20 Watch For unlimited access to Homework Help, a Homework+ subscription is required. WebNov 17, 2024 · let = x= [H+] = [CH2NH2] and 0.24 – x = [CH3NH3+] x^2/ (0.24 – x) = 2.29 * 10^-11. x^2 + 2.29 10^-11 – 5.49 10^-12 = 0. x = [H+] = 2.34 10^-6 M ==> pH = -log [H+] = … floating shelves instead of cabinets